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332x^2+83x=0
a = 332; b = 83; c = 0;
Δ = b2-4ac
Δ = 832-4·332·0
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(83)-83}{2*332}=\frac{-166}{664} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(83)+83}{2*332}=\frac{0}{664} =0 $
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